- Reaction score
- 8,339
- Points
- 1,160
Lumber said:Maybe I'm getting the context wrong, but at face value, I disagree with the completely. I don't want anyone doing any job that they don't want to be doing, especially running our legislature. Sure, make the job difficult, onerous, and demanding, but I want people who are passionate about what they are doing.
No one "wants" to go to war, kill people, and see their friends killed; but I don't want my next CO to hate his job either.
Brad Sallows said:This:
MCG said:Consider that London-West, London-North-Center, and London-Fanshaw could all be lumped into one riding of "London" with three MPs. In the last election, those three ridings elected one NDP (L-F) and two Liberals (L-NC and L-W), but as a single three member riding they would have elected one Conservative and two Liberals.
is what I mean by:
"This doesn't necessarily produce a result that is "more fair" in circumstances in which traditionally one-party ridings merge with ridings in which vote shares are more equally shared."
If a pocket of people in L-F want a NDP member for their locality, they should get one instead of another member decided in part for them by their neighbours.
I consider a system that allows representatives to be selected with non-majority pluralities, and majority governments to be formed with less than majority vote share, to be a great social stabilizer.
MCG said:Yet, it was a minority of people in L-F that decided they would have an NDP representative. Is that really more fair when what the city (inclusive of L-F) really wants is a Conservative?
Brad Sallows said:Yes, I consider it "more fair" (and healthier for the stability of the country) when people in a locality can choose a representative unencumbered by the preferences of people further away.
MCG said:It must be that you are being deliberately obtuse, given that the three London ridings together are all just one small "locality." Collectively these three ridings are a fraction of the size of any adjacent riding. Are the people of Lambton-Kent-Middlesex deprived of fairness as most of them are "encumbered by the preferences of people further away" to an extent that would be unachieved in the hypothetical three member riding that you use distance to argue against.
Brad Sallows said:Looking at a graphic of London from the 2015 election, I now see that the 2 x LPC and 1 x NDP ridings seem to be surrounded by CPC ridings. So I'm more convinced that the pocket of NDP supporters in London who can currently manage to elect a NDP representative - at least occasionally - get a fair shake from FPTP that they might never otherwise get in a multi-member riding. And, looking at Canada-wide results in general, it is clear that "locality" matters and in a densely populated area the political flavour of the population can change dramatically. But having lived in Metro Vancouver for years, I already knew this. Larger multi-member ridings mean shutting some people out too much of the time.
Representation is population-based. It doesn't have to be perfect, but those who want to have angels-on-a-pin discussions may go ahead.
MCG said:What you are feeling is called cognitive dissonance. If "locality matters" is your underlying premise against geographically small multi-member ridings, then it does not matter what surrounds the city of London when we are talking about voting results inside the city of London. Looking inside the city of London, 32% (almost 1/3) want a conservative MP but they do not get this under FPTP single representative ridings. A multi-member riding would give one conservative MP.
Which one? Are we even having the same conversation, or are you just posting baffle-gab nonsense? In a hypothetical three member riding consisting of the combined London-West, London-North-Center, and London-Fanshaw ridings the results of the last election show 32% support for the conservatives. That same hypothetical riding would have given the Conservatives one of the three seats had it existed in the last election.Brad Sallows said:Which one? I don't see how one of the Conservative candidates winning an MP's seat with 10-15% of the vote is an improvement over winning with 30-35%.
So I have applied the model to Vancouver and Victoria. In Vancouver the model would have given two additional Conservatives, two fewer Liberals, and an equal number of NDP being more geographically dispersed. That gives new national results as:MCG said:Agreed, and that means that any consideration of multi-member ridings would have to give voters the ability to select the individual MPs (ie. no party lists). Unfortunately, when working with FPTP results to model a hypothetical multi-member riding, the data just does not exist to replicate STV. It also does not let you model an independent ... Brent Rathgeber scored well enough in his riding that if other ridings provided him similar support he would have been a contender in a North Edmonton multi-member riding, but data only exists for the riding he actually ran in.
In any case, I extended the model of multi-member ridings across the country (less Vancouver and Victoria which I just did not get to) to get 36 multi-member ridings (including the ones already posted). I am sure threehundredeight.com could do a better job of this, but my model suggests use of big city multi-member ridings would have produced the following results in the 2015 election:
Liberal Conservative NDP Green BQ 163 112 44 1 11 -21 +13 +7 +0 +1
Attached are the ridings that I have not yet posted, if you want to see what the results would be in your neighbourhood.
Liberal | Conservative | NDP | Green | BQ | ||||
161 | 114 | 44 | 1 | 11 | ||||
-23 | +15 | +7 | +0 | +1 |
No. I have shown the math for each party running one candidate for each seat in the hypothetical multi-member ridings.Brad Sallows said:You seem to assume there would only be one CPC candidate running in a multi-member riding.
I did not make that assumption.Brad Sallows said:You've shown some vote counts, but how do you justify the assumption that all of the votes for each party are distributed among candidates with perfect efficiency?
jmt18325 said:Is it not possible to create a ballot where you rank party choices, and then within that rank your choice of candidates if you so choose?
No there is not "an implied assumption." The only undeclared assumption is being made by you. You have assumed that SNTV is the only voting option for a multi-member riding.Brad Sallows said:... there is still an implied assumption that the votes will somehow be distributed more efficiently, sufficiently to lift one of the (in the example of London) CPC candidates above the count obtained by the NDP member. That assumption applies in all cases: the distribution of votes for each member must actually be different for the outcomes to be different.
It is possible:jmt18325 said:Is it not possible to create a ballot where you rank party choices, and then within that rank your choice of candidates if you so choose?
Brad Sallows said:Whether you depend on the voters making a single SNTV choice each or an alternate mechanism, there is still an "assumption that the votes will somehow be distributed more efficiently". What alternate mechanism(s) would you propose to channel the outcome?
>Is it not possible to create a ballot where you rank party choices, and then within that rank your choice of candidates if you so choose?
A ranking system gives "anybody but" voters a mathematical advantage over "single preference" voters. A system which yields imbalanced strategic voting power should be discarded. (There must be no imbalances, because safeguarding the output legitimacy - essentially, the sense of a level playing field - is of paramount importance). That is one of the strong advantages of FPTP: every voter makes exactly one choice, with the same information, with no possible way of gaming a path through a decision tree.
Jed said:Sure it is possible. But what is the point of doing this?
No there is not.Brad Sallows said:Whether you depend on the voters making a single SNTV choice each or an alternate mechanism, there is still an "assumption that the votes will somehow be distributed more efficiently".
There is Single Transferable Vote or Schulze Transferable Vote.Brad Sallows said:What alternate mechanism(s) would you propose to channel the outcome?
The federal 2015 election shows that, informed by polls, the "anybody but" camp will just as easily organize a mathematical advantage in FPTP.Brad Sallows said:A ranking system gives "anybody but" voters a mathematical advantage over "single preference" voters.
I can game the FPTP system by running an irrelevant candidate with a platform similar to the contender(s) that I oppose, and in strong contrast to the contender(s) that I support. My irrelevant candidate stands no chance to win, but despite that my irrelevant candidate will draw votes away from those competitors that I want to loose while not affecting my preferred candidate.Brad Sallows said:That is one of the strong advantages of FPTP: every voter makes exactly one choice, with the same information, with no possible way of gaming a path through a decision tree.
MCG said:No there is not.
There is Single Transferable Vote or Schulze Transferable Vote.
The federal 2015 election shows that, informed by polls, the "anybody but" camp will just as easily organize a mathematical advantage in FPTP.
I can game the FPTP system by running an irrelevant candidate with a platform similar to the contender(s) that I oppose, and in strong contrast to the contender(s) that I support. My irrelevant candidate stands no chance to win, but despite that my irrelevant candidate will draw votes away from those competitors that I want to loose while not affecting my preferred candidate.
From 1997 to 2004, that split gave the Liberals a series of majority governments. It does work.Jed said:I have seen a couple of elections were that process did not work for gaming the system.
MCG said:From 1997 to 2004, that split gave the Liberals a series of majority governments. It does work.
Jed said:It worked because Quebec and Ontario could game the system not because FPTP.